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Khandice Schuhmann #2
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -1,33 +1,57 @@ | ||
// This method will return an array of arrays. | ||
// Each subarray will have strings which are anagrams of each other | ||
// Time Complexity: ? | ||
// Space Complexity: ? | ||
// Time Complexity: O(1) | ||
// Space Complexity: O(n) | ||
function groupedAnagrams(strings) { | ||
throw new Error("Method hasn't been implemented yet!"); | ||
anagramDict = {}; | ||
anagramsArray = []; | ||
|
||
for (let word of strings) { | ||
let temp = word.split("").sort().join(""); | ||
if (anagramDict.hasOwnProperty(temp)) { | ||
anagramsArray[anagramDict[temp]].push(word); | ||
} else { | ||
anagramDict[temp] = anagramsArray.length; | ||
anagramsArray[anagramDict[temp]] = [word]; | ||
} | ||
} | ||
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||
return anagramsArray; | ||
} | ||
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||
// This method will return the k most common elements | ||
// in the case of a tie it will select the first occuring element. | ||
// Time Complexity: ? | ||
// Space Complexity: ? | ||
// Time Complexity: O(n) | ||
// Space Complexity: O(n) | ||
function topKFrequentElements(list, k) { | ||
throw new Error("Method hasn't been implemented yet!"); | ||
} | ||
let frequency = {}; | ||
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||
for (let num of list) { | ||
if (num in frequency) { | ||
frequency[num] += 1; | ||
} else { | ||
frequency[num] = 1; | ||
} | ||
} | ||
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const freqArray = Object.entries(frequency).sort((a, b) => b[1] - a[1]); | ||
const sortArray = freqArray.map((element) => parseInt(element[0])); | ||
return sortArray.slice(0, k); | ||
} | ||
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// This method will return true if the table is still | ||
// a valid sudoku table. | ||
// Each element can either be a ".", or a digit 1-9 | ||
// The same digit cannot appear twice or more in the same | ||
// The same digit cannot appear twice or more in the same | ||
// row, column or 3x3 subgrid | ||
// Time Complexity: ? | ||
// Space Complexity: ? | ||
function validSudoku(table) { | ||
throw new Error("Method hasn't been implemented yet!"); | ||
throw new Error("Method hasn't been implemented yet!"); | ||
} | ||
|
||
module.exports = { | ||
groupedAnagrams, | ||
topKFrequentElements, | ||
validSudoku | ||
validSudoku, | ||
}; |
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This is O(n) time complexity, where n is the number of words. Yes, querying and updating
anagramDict
is O(1), but we have to do it n times.