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from symbl.utils.Threads import Thread
import symbl
import time
# here are all events supported by Telephony API, you just need to uncomment the event which you would like to use
events = {
'transcript_response': lambda transcript: print('printing the transcript response ', str(transcript))
,'message_response': lambda message: print('printing the message response ', str(message))
#,'insight_response': lambda insight: print('printing the insight response ', str(insight))
#,'topic_response': lambda topic: print('printing the topic response ', str(topic))
}
sip_uri = "sip:[email protected]"
connection_object = symbl.Telephony.start_sip(uri=sip_uri)
connection_object.subscribe(events)
normally i make this call with linphone with standard Setting and I coukd calling the client
when i use your library in python to do same thing the error coming :
raise ValueError('app_id is required') ValueError: app_id is required
i make a symbl.conf file and add the information
but i don#t sure what is the standard app_id and app_secret wich linephone used
I try : app_id ='admin' app_secret='administrator' come othe problem
The app_id and app_secret are the login creds for the Symbl Platform. You need to sign up on the platform, https://platform.symbl.ai/, and as soon as you login, you should see the app_id and app_secret on the main page.
Hallo
I try tu use you code example
normally i make this call with linphone with standard Setting and I coukd calling the client
when i use your library in python to do same thing the error coming :
raise ValueError('app_id is required') ValueError: app_id is required
i make a symbl.conf file and add the information
but i don#t sure what is the standard app_id and app_secret wich linephone used
I try : app_id ='admin' app_secret='administrator' come othe problem
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