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Create API KEY #5447
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Hello @topflyer! I'm here to help you with any bugs, questions, or contributions you have for Langflow. Let's work together to solve this issue. To resolve the unexpected error in Langflow after creating a new API key, ensure that the API key is valid and correctly set. You can use the Additionally, there are known issues related to API key management in Langflow, such as errors when saving the API key or invalid API key messages. Ensure that the API key is correctly set and that the context is properly managed to avoid unexpected errors [2]. To continue talking to Dosu, mention @dosu. Help Dosu learn! Give it feedback: Great Response | Irrelevant Answer | Incorrect Sources | Too Verbose | Hallucination | Other |
@dosu |
A 404 Not Found error in this context likely indicates that the flow with the ID Ensure that the flow ID is correct and that the flow exists. If the flow ID is valid and the flow should exist, double-check the UUID format and verify that the flow is accessible with the provided API key. To continue talking to Dosu, mention @dosu. Help Dosu learn! Give it feedback: Great Response | Irrelevant Answer | Incorrect Sources | Too Verbose | Hallucination | Other |
@dosu |
For the API request you're making, only the To continue talking to Dosu, mention @dosu. Help Dosu learn! Give it feedback: Great Response | Irrelevant Answer | Incorrect Sources | Too Verbose | Hallucination | Other |
@dosu |
Here's a sample code snippet for uploading a file to Langflow using Python: import httpx
from pathlib import Path
class UploadError(Exception):
"""Raised when an error occurs during the upload process."""
def upload(file_path: str, host: str, flow_id: str):
"""Upload a file to Langflow and return the file path.
Args:
file_path (str): The path to the file to be uploaded.
host (str): The host URL of Langflow.
flow_id (str): The ID of the flow to which the file belongs.
Returns:
dict: A dictionary containing the file path.
Raises:
UploadError: If an error occurs during the upload process.
"""
try:
url = f"{host}/api/v1/upload/{flow_id}"
with Path(file_path).open("rb") as file:
response = httpx.post(url, files={"file": file})
if response.status_code in {httpx.codes.OK, httpx.codes.CREATED}:
return response.json()
except Exception as e:
msg = f"Error uploading file: {e}"
raise UploadError(msg) from e
msg = f"Error uploading file: {response.status_code}"
raise UploadError(msg)
def upload_file(file_path: str, host: str, flow_id: str, components: list[str], tweaks: dict | None = None):
"""Upload a file to Langflow and return the file path.
Args:
file_path (str): The path to the file to be uploaded.
host (str): The host URL of Langflow.
flow_id (str): The ID of the flow to which the file belongs.
components (list[str]): List of component IDs or names that need the file.
tweaks (dict, optional): A dictionary of tweaks to be applied to the file.
Returns:
dict: A dictionary containing the file path and any tweaks that were applied.
Raises:
UploadError: If an error occurs during the upload process.
"""
try:
response = upload(file_path, host, flow_id)
except Exception as e:
msg = f"Error uploading file: {e}"
raise UploadError(msg) from e
if not tweaks:
tweaks = {}
if response["file_path"]:
for component in components:
if isinstance(component, str):
tweaks[component] = {"path": response["file_path"]}
else:
msg = f"Error uploading file: component ID or name must be a string. Got {type(component)}"
raise UploadError(msg)
return tweaks
msg = "Error uploading file"
raise UploadError(msg) This code provides functions to upload a file to Langflow. The To continue talking to Dosu, mention @dosu. Help Dosu learn! Give it feedback: Great Response | Irrelevant Answer | Incorrect Sources | Too Verbose | Hallucination | Other |
@dosu |
To integrate the Langflow file upload functionality into your FastAPI application using an API, you can use the following code snippet: from fastapi import FastAPI, UploadFile, File, HTTPException
import httpx
app = FastAPI()
@app.post("/upload/{flow_id}")
async def upload_file_to_langflow(flow_id: str, file: UploadFile = File(...)):
url = f"http://langflow-api-url/api/v1/files/upload/{flow_id}"
headers = {"x-api-key": "YOUR_API_KEY"} # Replace with your actual API key
try:
async with httpx.AsyncClient() as client:
response = await client.post(
url,
files={"file": (file.filename, file.file, file.content_type)},
headers=headers
)
response.raise_for_status()
return response.json()
except httpx.HTTPStatusError as e:
raise HTTPException(status_code=e.response.status_code, detail=e.response.text) Replace To continue talking to Dosu, mention @dosu. Help Dosu learn! Give it feedback: Great Response | Irrelevant Answer | Incorrect Sources | Too Verbose | Hallucination | Other |
I created new langflow API key and it is errors
Error message is.
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