how get the originalUrl (the incoming HTTP request from Node core)

[guoxiangke]

Hi, I build a redirect app with honojs.
I need the origin raw incoming url, how to get it in c.req.url?
I found the : https://fastify.dev/docs/latest/Reference/Request/ has a raw method.
does honojs has one like that? thanks.
raw - the incoming HTTP request from Node core
url - the URL of the incoming request
originalUrl - similar to url, this allows you to access the original url in case of internal re-routing

the reason why I want is that:
I want
http://localhost:3000/api?redirect=http://napi.yageapp.com/api/t.php?k=6b42e8370481f752?metric=NFC%26keyword=nav%26target=%E7%9B%9F%E7%BA%A6%E8%AF%97%E6%AD%8C
redirect to
http://napi.yageapp.com/api/t.php?k=6b42e8370481f752

YES! there are more than 1 ?

[NicoPlyley]

I am not sure if I understand what your are asking
Here is my code

import { Hono } from 'hono';

app.get('/', async (c) => {
  const path = c.req.url;

  return c.text(path);
});


export default app;

And when I go to http://localhost:3000/?redirect=http://napi.yageapp.com/api/t.php?k=6b42e8370481f752?metric=NFC%26keyword=nav%26target=%E7%9B%9F%E7%BA%A6%E8%AF%97%E6%AD%8C

The result I get is the exact same as entered.

If I want to redirect it to the entered url this works just fine

app.get('/', async (c) => {
  const path = c.req.query('redirect');

  if (!path) {
    return c.json({ success: false });
  }

  return c.redirect(path);
});